Worksheet for Section 2.5
Secton 2.5 is about the second derivative, and what information it
gives about the graph of a function. First, note that the sign of the
derivative
of a function
indicates whether the
function
is increasing or decreasing:
- A function
is increasing on an interval if for any
two numbers
and
in the interval,
implies
.
- A function
is decreasing on an interval if for any
two numbers
and
in the interval,
implies
.
More intuitively, a function is increasing if it is going up from left to
right in its graph,
decreasing if it is going down from left to right. This description,
though, suggests a connection with derivatives -- if
is
continuous on
and differentiable on
, then the derivative
gives the following information:
- If
for all
in
, then
is
increasing on
.
- If
for all
in
, then
is
decreasing on
.
- If
for all
in
, then
is
constant (neither increasing nor decreasing) on
.
Determine the intervals where each of the
following functions are increasing or decreasing:
(All of these are functions for which you computed derivative functions
in Section 2.3.)
- A function
is concave upward on an open interval
if
is increasing on
.
- A function
is concave downward on an open interval
if
is decreasing on
.
Since the information about whether
is increasing or decreasing
can be determined from the
sign of the derivative of
,
i.e. from the sign of the second derivative
,
the concavity (concave upward or concave downward) of
can be determined from the sign of
:
- If
for all
in the open interval
, then
is concave upward on
.
- If
for all
in the open interval
, then
is concave downward on
.
Here are some examples -- for each function, find the intervals where
the function is concave upward or concave downward.
(All of these are functions for which you computed derivative functions
in Section 2.3.)
An inflection point is a point on the graph of a function where
the graph's concavity changes -- so where the sign of
changes.
Where do the functions above have inflection points?
Regarding the derivative as a rate of change gives a physical interpretation
of the second derivative as well. Recall that the instantaneous rate of
change in the position of an object is its velocity -- this is the
derivative of the position function. The second derivative, then is the
instantaneous rate of change in the velocity function -- in other words,
the acceleration. For example, recall the falling object problem from
Section 2.1, where the position (in this case, height) of the object at
time
was given by the function
. What is the
acceleration of the object, as a function of time
? (At this point,
you will need to compute this using the limit definition of the
derivative twice.)
Thomas E. Leathrum
2007-08-27